Boiling point of water of 750 mm Hg is 99-63- C- How much sucrose is to be added to 500 g of water such that it boils at 100-02- C - Molar elevation constant for water is 0-52 Kkgmol -1-A- 121-7 gB- 128-25 gC- 1217 gD- 12825 g

Elevation in boiling point required nbsp; (Δ T_b)=100 99.63=0.37^∘C Mass of solvent (water), W_1=500 g Molar mass of solvent, M_1=18 g/mol Molar mass of solut ...

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Byju's Answer

Standard XII

Chemistry

Liquids in Liquids

Boiling point...

Question

Boiling point of water of $750 mm Hg$ is ${99.63}^{\circ} C$ . How much sucrose is to be added to $500 g$ of water such that it boils at ${100.02}^{\circ} C$ ?

Molar elevation constant for water is $0.52 {Kkgmol}^{- 1}$ .

121.7 g

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128.25 g

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1217 g

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12825 g

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Solution

The correct option is A $121.7 g$
Applying formula, $M_{2} = \frac{1000 \times K_{b} \times W_{2}}{W_{1} \times Δ T_{b}}$

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Similar questions

Boiling point of water at 750 mm Hg is 99.63°C. How much sucrose is to be added to 500 g of water such that it boils at 100°C. Molal elevation constant for water is 0.52 K kg mol⁻¹.

Q. Boiling point of water at

750 m m H g

{99.63}^{\circ} C

. How much sucrose is to be added to

500 g

of water such that it boils at

100^{\circ} C

How many moles of sucrose should be dissolved in 500 g of water so as to get a solution which has a difference of $104^{\circ} C$ between boiling point and freezing point. $(K_{f} = 1.86 K k g m o l^{- 1}, K_{b} = 0.52 K k g m o l^{- 1})$ .