Question

Bombardment of aluminium of α-particle leads to its artificial disintegration in two ways (i) and (ii) as shown below. Product X, Y, and Z, respectively, are

${}_{14}S{i}^{30}+X\stackrel{\left(i\right)}{\leftarrow }{}_{13}A{l}^{27}\stackrel{\left(ii\right)}{\to }{}_{15}{P}^{30}+Y\to {}_{14}S{i}^{30}+Z$

(IIT-JEE, 2011)

• A. Proton, neutron, positron
• B. Neutron, positron, proton
• C. Proton, positron, neutron
• D. Positron, proton, neutron

Answer 1

The correct option is A

Proton, neutron, positron

${}_{13}A{l}^{27}{\stackrel{{}_{2}H{e}^4}{\to }}_{15}{P}^{30}{+}_0{n}^1\left(y\right)$

${}_{2}H{e}^4\downarrow \left(i\right)\downarrow \left(ii\right)$

${}_{14}S{i}^{30}{+}_{1}P\left(x{)}^1{}_{14}S{i}^{30}{+}_1{e}^{+0}\right(z)$

∴ x: Protons, y: neutron, z: positron