Question

Bond angle between two hybrid orbitals is ${107}^0$, s - orbital character of hybrid orbital is nearly:

• A. $50$%
• B. $33.33$%
• C. $16.6$%
• D. $25$%

Answer 1

The correct option is D $25$%

The bond angle ${107}^0$ suggests $s{p}^3$ hybridization as it is nearer $109^o{28}^{\prime }$.

In $s{p}^3$, the '$s$' character is of $25$% and '$p$' character is of $75$%.

So, the correct option is $D.$