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Question

Bond dissociation enthalpies of H2(s) and N2(g) are 436.0 kJ mol1 and enthalpy of formation of NH3(g) is 46 kJ mol1. What is enthalpy of atomization of NH3(g)? What is the average bond enthalpy of NH bond?

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Solution

N2(g)+3H2(g)2NH3(g);ΔH=2×46kJ/mol
ΔH=(BE)R(BE)P=(941.8+3×436)(6x)=2×46
(here x=BE of N-H bond)
x=390kJmol1
NH3N+3H
Heat of atomization =3×390.3=1170.9kJmol1

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