Bond distance C−H in CH4 is x∘A and that of Si−H in SiH4 is y∘A. C−Si bond is z∘A. Calculate covalent radii of H atom igonoring the electronegativity difference.
A
x+y+z2
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B
x+y−z2
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C
x−y−z2
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D
x+y2
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Solution
The correct option is Bx+y−z2 Consider The radius of H atom =rH∘A The radius of C atom =rC∘A The radius of Si atom =rSi∘A Given bondlength of C−H=x∘A Bond length of Si−H=y∘A Bond length of C−Si=z∘A Value of bond length of C - H rH+rC=x−(i) Value of bond length of Si-H =rSi+rH=y−(ii) Value of bond length of C-Si =rC+rSi=z(iii) Solving (i) (ii) and (iii) Value of rH=x+y−z2∘A