Bond energies in $N O, N O^{+}, N O^{-}$ are such as:

N O^{-} > N O > N O^{+}

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N O > N O^{-} > N O^{+}

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N O^{+} > N O > N O^{-}

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N O^{+} > N O^{-} > N O

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Solution

The correct option is D $N O^{+} > N O > N O^{-}$
Bond order of $N O^{+}, N O$ and $N O^{-}$ are $3, 2, 5$ and $2$ respectively.
Bond energy $\propto$ bond order.

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Similar questions

Bond energies in $N O, N O^{+}$ and $N O^{-}$ are such as

N - O

N O_{2}^{+}

N O_{2}^{-}

N O_{3}^{-}

N O_{2}^{+}, N O_{2}^{-}

N O_{3}^{-}

N - O

N O^{+}

N O^{-}

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