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Physical Properties of Carbon Family

Bond energy o...

Question

Bond energy of ${C l}_{2}, {B r}_{2}$ and $I_{2}$ follow the order :

{C l}_{2} > {B r}_{2} > I_{2}

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{B r}_{2} > {C l}_{2} > I_{2}

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I_{2} > {B r}_{2} > {C l}_{2}

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I_{2} > {C l}_{2} > {B r}_{2}

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Solution

The correct option is A ${C l}_{2} > {B r}_{2} > I_{2}$
As we move from top to bottom in halogen family the bond energy of the molecules decreases as the bond distance increases. As the bond distance increases it requires less energy to break the bond i.e. less bond energy.

So, the order of bond energy of the molecules is $C l_{2} > B r_{2} > I_{2}$ .

Hence option A is correct.

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Similar questions

The correct order of the oxidizing power of Cl₂, Br₂, I₂ and O₂ is:

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

(x^{2} + y^{2})

x

y

F_{2}, C l_{2}, B r_{2}, I_{2}

B r_{2}

I_{2}

C l_{2}

C l_{2}

B r_{2}

I_{2}

I_{2}, {B r}_{2}, {C l}_{2}, F_{2}

I_{2} < {B r}_{2} < {C l}_{2} < F_{2}

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