Bond energy of $F_{2}, C l_{2}$ and $B r_{2}$ follow the order:

F - F > C l - C l > B r - B r

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C l - C l > B r - B r > F - F

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B r - B r > C l - C l > F - F

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C l - C l > F - F > B r - B r

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Solution

The correct option is A $C l - C l > B r - B r > F - F$
The order of bond energy is :

$C l - C l (57 k c a l / m o l) > B r - B r (45.5 k c a l / m o l) > F - F (38 k c a l / m o l)$

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Similar questions

Q. The correct order of polarizability is

I^{-}, B r^{-}, C l^{-}, F^{-}

Among halogens, the correct order of amount of energy released in electron gain (electron gain enthalpy ) is
(a) F > Cl > Br > I (b) F < Cl < Br < I (c) F < Cl > Br > I (d) F < Cl < Br < I

Q. The decreasing order of electron affinity of

F, C l, B r i s F > C l > B r

Q. Arrange the following bonds according to their average bond energies in descending order:

C - C l, C - B r, C - F, C - I

Q. Which of the following options does not give to the correct trends indicated against it?
(I)

F_{2} > C l_{2} > B r_{2} > I_{2}

: Bond dissociation energy
(II)

F_{2} > C l_{2} > B r_{2} > I_{2}

: Oxidizing nature
(III)

C l > F > B r > I

: Electron gain enthalpy
(IV)

F > C l > B r > I

: Electronegativity

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Bond energy of F2,Cl2 and Br2 follow the order:

The correct option is A Cl−Cl>Br−Br>F−FThe order of bond energy is : Cl−Cl(57kcal/mol)>Br−Br(45.5kcal/mol)>F−F(38kcal/mol)

Bond energy of $F_{2}, C l_{2}$ and $B r_{2}$ follow the order:

The correct option is A $C l - C l > B r - B r > F - F$
The order of bond energy is :

$C l - C l (57 k c a l / m o l) > B r - B r (45.5 k c a l / m o l) > F - F (38 k c a l / m o l)$