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Resonance

Bond energy o...

Question

Bond energy of $H - H, F - F$ and $H - F$ bonds are $104, 38$ and $135$ kcal mol $^{- 1}$ respectively. Resonance energy (in $k c a l m o l^{- 1}$ ) in the $H - F$ molecule is :

72.14

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42.44

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78.34

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none of these

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Solution

The correct option is A $72.14$
Resonance energy, $△_{H - F} = (B E)_{H - F} - \sqrt{(B H)_{H_{2}} (B E)_{F_{2}}}$
$= 135 - \sqrt{104 \times 38}$
$= 135 - 62.86$
$= 72.14 k c a l m o l^{- 1}$

Suggest Corrections

Similar questions

E_{H - H} = 104.2 k c a l m o l^{- 1}

E_{F - F} = 36.6 k c a l m o l^{- 1}

E_{H - F} = 134.6 k c a l m o l^{- l}

X_{H} = 2.1.

E_{H - H} = 104.2 k c a l m o l^{- 1}

E_{F - F} = 36.6 k c a l m o l^{- 1}

E_{H - F} = 134.6 k c a l m o l^{- l}

X_{H} = 2.1.

Δ H

O F_{2} (g) + H_{2} O (g) ⟶ O_{2} (g) + 2 H F (g)

O - F

O - H

O = O

H - F

44

111

118

135

^{- 1}

Δ H_{f} (H) = 218 k J / m o l

H - H

k c a l / m o l

H - H b o n d = 434 k J m o l^{- 1}

F - F b o n d = 158 k J m o l^{- 1}

H - F b o n d = 565 k J m o l - 1

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