Question

Bond length can be calculated by merely adding covalent bond radii which are$H$ = $0.28$ $\mathring{A}$, $N$ = $0.70$ $\mathring{A}$, $O=$ $0.66$ $\mathring{A}$, $Cl=$ $0.99$ $\mathring{A}$, $(C=)$=$0.67$$\mathring{A}$,$(C$$\equiv$)=$0.61$ $\mathring{A}$, (N$\equiv$)= $0.55$ $\mathring{A}$ and $(C-)=0.77A^o$. Calculate bond lengths in $HOCl$.

• A. $O-H=0.94\mathring{A};O-Cl=1.65\mathring{A}$
• B. $O-H=0.04\mathring{A};O-Cl=1.65\mathring{A}$
• C. $O-H=0.94\mathring{A};O-Cl=1.85\mathring{A}$
• D. None of these

Answer 1

The correct option is A $O-H=0.94\mathring{A};O-Cl=1.65\mathring{A}$

Bond length can be calculated by merely adding covalent bond radii.$O-H$ has single bond and $O-Cl$ has single bond. Adding the corresponding bond lengths: $OH:0.98A;OCl:1.65A^0$