Bond - length of HCl is 1-275-Ae -4-8 -10-10esu- If dipole moment - 1-02 D -then HCl is-

The bond length of HCl bond is $2.29 \times 10^{- 10} m$ . The percentage ionic character of HCl, if measured dipole moment is $6.226 \times 10^{- 30} C . m$ is

Q. The percentage ionic character of a bond having

1.257 A^{0}

its length and

1.03

D its dipole moment is:
(

q = 4.8 \times 10^{- 10}

esu)

Q. The bond length of

H C l

bond is

2.29 \times 10^{- 10} m

. The percentage ionic character of

H C l

, if measured dipole moment is

6.226 \times 10^{- 30} C - m

, is:

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Bond - length of HCl is 1.275∘A(e=4.8×10−10esu). If dipole moment =1.02D ,then HCl is:

The correct option is A 83% covalentPercentage of ionic character=1.021⋅275×4⋅8×100=16⋅82% , i.e., around 17% ionic(100−17)=83% covalent

Bond - length of $H C l$ is $1.275 \circ A$ (e $= 4.8 \times 10^{- 10}$ esu). If dipole moment $= 1.02 D$ ,then $H C l$ is:

The correct option is A $83$ % covalent
Percentage of ionic character
$= \frac{1.02}{1 \cdot 275 \times 4 \cdot 8} \times 100 = 16 \cdot 82$ % , i.e., around $17$ % ionic
$(100 - 17) = 83$ % covalent