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Bond Order by MOT

Bond order in...

Question

Bond order in compound $P O_{4}^{- 3}$ is:

1

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2

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1.25

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1.33

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Solution

The correct option is C $1.25$

Phosphate ion ${P O}_{4}^{3 -}$ has following structure
Bond order $= \frac{N o . o f r e s o n a t i n g b o n d}{N o . o f a t o m}$
$= \frac{1}{4} = 0.25$
Bond order $= 1 + 0.25 = 1.25$

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