Question

Bond order of $B{e}_2$ is:

• A. 1
• B. 2
• C. 3
• D. 0.0

Answer 1

The correct option is D 0.0

Bond order $=\frac{N_b-N_a}{2}$
$N_b=$ total number of bonding electrons
$N_a=$ total number of antibonding electrons

$B{e}_2=\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2$
Bond order $=\frac{N_b-N_a}{2}$
$=\frac{4-4}{2}$ $=0$
So, $B{e}_2$ does not exist.