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Nitrogen

Bond-order of...

Question

Bond-order of $H e_{2}^{2 +}$ is ...........

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Solution

The bond order of $H e_{2}^{2 +}$ is $1$ .
It contains only $2$ valence electrons.
$(σ 1 s)^{2}$
Thus there are $2$ bonding electrons and zero non bonding electrons.
Thus, the bond order is $\frac{2 - 0}{2} = 1$ .

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