Borazine can be prepared by heating:

B_{2} H_{6} + N F_{3}

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[B H_{2} (N H_{3})_{2}]^{+} [B H_{4}]^{-}

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[B H_{3} (N H_{3})_{2}]^{+} [B H_{2}]^{-}

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(B H_{3} (N H_{4})_{4}]^{+} [B H_{2}]^{-}

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Solution

The correct option is B $[B H_{2} (N H_{3})_{2}]^{+} [B H_{4}]^{-}$
$B_{2} H_{6} + N F_{3}$ are the products of the reaction given below:
$2 B F_{3} + 2 N H_{3} \to B_{2} H_{6} + N F_{3}$

Borazine can be prepared by heating the intermediate $[B H_{2} (N H_{3})_{2}]^{+} [B H_{4}]^{-}$ .

$B_{2} H_{6} + 2 N H_{3} - 120^{o} C - ---- \to [B H_{2} (N H_{3})_{2}]^{+} [B H_{4}]^{-} Δ - --- \to 200^{o} C 2 B_{3} N_{3} H_{6} + 12 H_{2}$

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