Boric acid on heating at $100^{o} C$ gives:

B_{2} O_{3}

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H_{2} B_{4} O_{7}

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H B O_{2}

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H_{2} B O_{3}

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Solution

The correct option is A $H B O_{2}$
Orthoboric acid, $H_{3} B O_{3}$ is a white crystalline solid, with soapy touch. It is sparingly soluble in water but highly soluble in hot water.
On heating, orthoboric acid above 370K forms metaboric acid, $H B O_{2}$ which on further heating yields boric oxide, $B_{2} O_{3} .$
Hence option C is correct answer.

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