Question

Boron is an effective absorber of neutrons. When boron-10 adds a neutron, $\alpha$-particles are emitted. The balanced equation for this nuclear reaction is:

• A. ${}_5^{10}B+{}_0^{1}n⟶{}_3^{7}Li+{}_2^4\underset{\left(\alpha \right)}{H}e$
• B. ${}_5^{15}B+{}_0^{1}n⟶{}_3^{5}Li+{}_2^4\underset{\left(\alpha \right)}{H}e$
• C. ${}_5^{12}B+6_0^{1}n⟶{}_3^{7}Li+{}_2^4\underset{\left(\alpha \right)}{H}e$
• D. none of these

Answer 1

The correct option is A ${}_5^{10}B+{}_0^{1}n⟶{}_3^{7}Li+{}_2^4\underset{\left(\alpha \right)}{H}e$

Boron is an effective absorber of neutrons. When boron-10 adds a neutron, an $\alpha -$particles is emitted. The daugther nuclues formed is Li-7. The balanced equation for this nuclear reaction is
${}_5^{10}B+{}_0^{1}n⟶{}_3^{7}Li+{}_2^4\underset{\left(\alpha \right)}{H}e$