Boron is prepared by heating of:

B C l_{3}

with HCl

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N a_{2} B_{4} O_{7}

with

C l_{2}

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boron halides with

L i A l H_{4}

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B_{2} O_{3}

with Mg

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Solution

The correct option is D $B_{2} O_{3}$ with Mg
Boron is prepared by heating of $B_{2} O_{3}$ with Mg.
The reaction is:
$B_{2} O_{3} + 3 M g \to 2 B + 3 M g O$

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Similar questions

B_{2} O_{3}

B $_{2}$ O $_{3}$ + C + Cl $_{2}$ $\to A + B . A & B$ are?

B $_{2}$ O $_{3}$ + C + Cl $_{2}$ $\to A + B . A & B$ follows

B C l_{3} (e x c e s s) L i A l H_{4} - --- \to e t h e r (A) (i) E x c e s s o f N H_{3} - ---------- \to (i i) H i g h t t e m p (B)

R - X + M g E t_{2} O - -- \to R M g X

A r - X + M g E t_{2} O - -- \to A r M g X

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