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Oxides of Sulphur

Boron triflou...

Question

Boron triflouride reacts with sodium hydride at $450 K$ to form $^{'} A^{'}$ and $N a F$ . $^{'} A^{'}$ is mixed with excess $N H_{3}$ and heated at higher temperature to form $^{'} B^{'}$ . The formula of $^{'} B^{'}$ is:

A

H_{3} B O_{3}

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B

(B N)_{x}

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C

B_{2} H_{6}

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D

B_{3} N_{3} H_{6}

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Solution

The correct option is B $(B N)_{x}$
$2 B F_{3} + 6 N a H 450 K - -- \to B_{2} H_{6} (A) + 6 N a F B_{2} H_{6} + N H_{3 (excess)} H i g h e r - ------ \to t e m p e r a t u r e (B N)_{x} (B)$

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