Question

Both Arjun and Rahul went for jogging the next day and stopped at a place where kids were playing on a slide as shown below:

Two slides which are directed in the two opposite directions are combined with the vertical stairs in the midway between the two sliders. The lengths of both the slides are same.

Two kids Mia and Anu reached down after sliding. How much distance Mia has to walk from $A$ to reach Anu who is at $B,$ if $AC=5m$ and width of the stairs $=1m?$

• A. 10 m
• B. 6 m
• C. 5 m
• D. 11 m

Answer 1

The correct option is D

11 m

If you consider $\Delta ACE$ and $\Delta BDF,$

Given that, distances kids slide on both the sliders are same.

$\Rightarrow AE=FB$

$EC=FD$ [height of the stairs]

$\angle ACE=\angle FDB={90}^{\circ }$ [Since, the stairs are vertical]

$\Rightarrow \Delta ACE$ and $\Delta BDF$ are congruent using RHS congruency criterion

$\Rightarrow AC=DB=5m$

The distance Mia has to walk reach Anu $=AC+CD+DB=5+1+5=11m$