Question

Both $\left[Ni\right(CO{)}_4]$ and $\left[Ni\right(CN{)}_4{]}^{2-}$ are diamagnetic. The hybridisations of nickel in these complexes respectively are

• A. $s{p}^3,s{p}^3$
• B. $s{p}^3,ds{p}^2$
• C. $ds{p}^2,s{p}^3$
• D. $ds{p}^2,ds{p}^2$

Answer 1

The correct option is B $s{p}^3,ds{p}^2$

$\left[Ni\right(CO{)}_4]$ is tetrahedral and has $s{p}^3$ hybridisation while $\left[Ni\right(CN{)}_4{]}^{2-}$ is square planar and has $ds{p}^2$ hybridisation.