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Question

Both oxidation and reduction takes place in :

A
NaBr+HClNaCl+HBr
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B
HBr+AgNO3AgBr+HNO3
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C
H2+Br22HBr
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D
CaO+H2SO4CaSO4+H2O
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Solution

The correct option is C H2+Br22HBr
H2+Br22HBr
As H has 0(zero) O.S. in H2, same in Br it has also 0 (zero ) O.S..
Now as in HBr , H has +1 O.S. whereas in Br, it has -1 , O.S.
As 0 to +1 change is oxidation and 0 to -1 is reduction.
so in this both oxidation and reduction taking place.

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