Both the nucleus and the atom of some element are in their respective first excited states. They get de-excited by emitting photons of wavelengths λ N, λ Arespectively. Then their ratio is closest to

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Q. Both the nucleus and the atom of some element are in their respective first excited states. They get de-excited by emitting photons of wavelengths

λ_{N}, λ_{A}

respectively. The ratio

\frac{λ_{N}}{λ_{A}}

is closest to

Q. A hydrogen-like atom (atomic number

Z

) is in a higher excited state of quantum number

n

. This excited atom can make a transition to the first excited state by successively emitting two photons of energies

10.2 e V

and

17.0 e V

, respectively. Alternatively, the atom from the same excited state can make a transition to the second excited state by successively emitting two photons of energies

4.25 e V

and

5.95 e V

, respectively. The values of

n

and

Z

are, respectively

Q. The electron in a hydrogen atom first jumps from the third excited state to the second excited state and subsequently to the first excited state. The ratio of the respective wavelengths,

λ_{1} / λ_{2}

of the photons emitted in this process is:

An electron in hydrogen atom first jumps from second excited state to first excited state and then from first excited state to ground state. Let the ratio of wavelength, momentum and energy of photons emitted in these two cases be a, b and c respectively. Then

Q. A hydrogen-like atom with the atomic number

Z

is in the higher excited state of the quantum number

^{'} n^{'}

. This excited state atom can make a transition to the first excited state by successively emitted two photons of energy 10.2 eV and 17eV respectively.

Alternatively, the atom from the same excited state can make a transition to the 2nd excited state by emitting photons of energy 4.25 eV and 5.95 eV, respectively. Determine

Z

and

n

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