Both the roots of x2 - 63x + k = 0 are prime numbers. Then the sum of the digits of k is
5
Let p, q be the roots which are primes.
∴ p + q = 63 is odd ⇒ one of p or q is the even prime 2 ⇒ other is 61.
∴ k = 61 x 2 = 122.
Sum of the digits of k = 5.
Answer : Sum of the digits of k = 5.