Question

Both the strings, shown in figure, are made of same material and have same cross-section. The pulleys are light. The wave speed of a transverse wave in the string $AB$ is $v_1$ and in $CD$ it is $v_2$. Then $\frac{v_1}{v_2}$ is

• A. 1
• B. 2
• C.
• D.

Answer 1

The correct option is D

Tension in string $AB$ = $T$

Tension in string $CD$ = $2T$

$V$ $\propto$ $\sqrt{T}$ $\Rightarrow$ $\frac{V_1}{V_2}$ = $\sqrt{\frac{T}{2T}}$ = $\frac{1}{\sqrt{2}}$