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Function Implementation Using CMOS

Both transisi...

Question

Both transisitors $T_{1} a n d T_{2}$ shown in the figure, have a threshold voltage of 1 Volts. The device parameters $K_{1} a n d K_{2}$ of $T_{1} a n d T_{2}$ are, respectively, 36 $μ A / V^{2}$ and 9 $μ A / V^{2}$ . The output voltage $V_{0}$ is

2 V

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1 V

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4 V

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3 V

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Solution

The correct option is D 3 V
$I_{D_{1}} = I_{D_{2}}$
$K_{1} (V_{G S_{1}} - V_{t})^{2} = K_{2} (V_{G S_{2}} - V_{t})^{2}$
$\Rightarrow$ $36 (5 - V_{0} - 1)^{2} = 9 (V_{0} - 0 - 1)^{2}$
$\Rightarrow$ $V_{0} = 3 V$

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Both transisitors T1 and T2 shown in the figure, have a threshold voltage of 1 Volts. The device parameters K1 and K2 of T1 and T2 are, respectively, 36 μA/V2 and 9 μA/V2. The output voltage V0 is

The correct option is D 3 V ID1=ID2 K1(VGS1−Vt)2=K2(VGS2−Vt)2 ⇒ 36(5−V0−1)2=9(V0−0−1)2 ⇒ V0=3 V

Both transisitors $T_{1} a n d T_{2}$ shown in the figure, have a threshold voltage of 1 Volts. The device parameters $K_{1} a n d K_{2}$ of $T_{1} a n d T_{2}$ are, respectively, 36 $μ A / V^{2}$ and 9 $μ A / V^{2}$ . The output voltage $V_{0}$ is

The correct option is D 3 V
$I_{D_{1}} = I_{D_{2}}$
$K_{1} (V_{G S_{1}} - V_{t})^{2} = K_{2} (V_{G S_{2}} - V_{t})^{2}$
$\Rightarrow$ $36 (5 - V_{0} - 1)^{2} = 9 (V_{0} - 0 - 1)^{2}$
$\Rightarrow$ $V_{0} = 3 V$