Question

Question 2

Both x and y vary inversely with each other. When x is 10, y is 6, which of the following is not a possible pair of corresponding values of x and y?
(a) 12 and 5
(b) 15 and 4
(c) 25 and 2.4
(d) 45 and 1.3

Answer 1

Since, x and y vary inversely, i.e. $x\times y=k$ (constant)
If x =10 and y =6
$\therefore xy=10\times 6=60$
In option (a),$12\times 5=60$
In option (b),$15\times 4=60$
In option (c),$24\times 2.4=60$
But in option (d), $45\times 1.3=58.3$
Hence, option (d)is correct.