Question

$\square$ABCD is a cyclic Quadrilateral. If $\angle A-\angle C=30$ then

Find $\angle A$ and $\angle B$

Answer 1

We have,

$\square ABCD$is acyclic quadrilateral.

If $\angle A-\angle C={30}^o......\left(1\right)$

Then,

We know that,

In a cyclic quadrilateral.

$\angle A+\angle C={180}^o......\left(2\right)$

From equation (1) and (2) to and we get,

$2\angle A={210}^o$

$\angle A={105}^o$

$\angle B={75}^o$

Hence, this is the answer.