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Standard VI

Mathematics

Area of Square

PQRS is a rec...

Question

$□ P Q R S$ is a rectangle. If $P Q + Q R = 7$ and $P R + Q S = 10$ , find the area of $□ P Q R S$ .

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Solution

Given that :
$P Q + Q R = 7$ unit
$P R + Q S = 10$ unit

Area of rectangle $= (l \times b)$
$= 7 \times 10$
$= 70 u n i t .$

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In Fig. PQRS is a quadrilateral in which diagonals PR and QS intersect in O. [4 MARKS]

Show that:
(i) PQ + QR + RS + SP $>$ PR + QS
(ii) PQ + QR + RS + SP $<$ 2 (PR + QS)

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□PQRS is a rectangle. If PQ+QR=7 and PR+QS=10, find the area of □PQRS.

Given that : PQ+QR=7 unitPR+QS=10 unitArea of rectangle =(l×b)=7×10=70 unit.

$□ P Q R S$ is a rectangle. If $P Q + Q R = 7$ and $P R + Q S = 10$ , find the area of $□ P Q R S$ .

Given that :
$P Q + Q R = 7$ unit
$P R + Q S = 10$ unit

Area of rectangle $= (l \times b)$
$= 7 \times 10$
$= 70 u n i t .$