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Boyle's Law

Boyles Law is...

Question

Boyles Law is given by :

A

q = m c Δ T

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B

q = H_{V} m

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C

P_{1} V_{1} = P_{2} V_{2}

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D

D = m / V

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E

K = C + 273

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Solution

The correct option is C $P_{1} V_{1} = P_{2} V_{2}$
According to Boyle's Law, $P_{1} V_{1} = P_{2} V_{2}$ .
For a given mass of a gas, the product of pressure and volume is always constant at constant temperature.
$P V =$ constant

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Similar questions

Q. Which gas law is summarized with the following equation?

P_{1} V_{1} = P_{2} V_{2}

For an ideal gas, an illustration of three different paths

A

(B + C)

(D + E)

from an initial state

P_{1}

V_{1}

T_{1}

to a final state

P_{2}

V_{2}

T_{1}

is shown in the given figure.
Path

A

represents a reversible Isothermal expansion from

P_{1}

V_{1}

P_{2}, V_{2}

(B + C)

reperesents a reversible adiabatic expansion

(B)

P_{1} V_{1}

T_{1}

P_{3}

V_{2}

T_{2}

followed by reversible heating the gas at constant volume

(C)

P_{3}

V_{2}

T_{2}

P_{2}

V_{2}

T_{1}

(D + E)

represents a reversible expansion at constant pressure

P_{1} (D)

P_{1}

V_{1}

T_{1}

P_{1}

V_{2}

T_{3}

followed by a reversible cooling at constant volume

V_{2} (E)

P_{1}

V_{2}

T_{3}

P_{2}

V_{2}

T_{1}

Δ S

(D + E) ?

Q. A thermodynamical system is changed from state

(P_{1}, V_{1})

(P_{2}, V_{2})

by two different processes. The quantity which will remain same will be:

Q. The velocities of sound at the same temperature in two monoatomic gases of densities

p_{1}

p_{2}

v_{1}

v_{2}

respectively. If

p_{1} / p_{2} = 4

, then the value of

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Q. An ideal gas follows a process described by

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(P_{2}, V_{2}, T_{2})

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