BP > PC
If the above statement is true then mention answer as 1, else mention 0 if false

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Solution

Since , $△ A B C$ is an equilateral triangle, all
angles $= 60^{0}$
Clearly, $∠ P C B > ∠ C B P$ as $∠ C B P$ is a part of the
angle $60^{o}$
Hence, the sides opposite to the angles will also have the same relation.
$=> B P > P C$

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