~~1. What is the amount of work done by: a) the Earth’s gravitational force in keeping the moon in its circular orbit around the Earth. b)an electron moving with half the speed of light in empty space free of all forces and far from all matters?

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Solution

Dear student,

(a) Work done = $\vec{F} . \vec{d s}$
Direction of displacement is always perpendicular to the gravitational force in circular motion, So work done is zero.

(b) Work done = $\vec{F} . \vec{d s}$
Velocity of electron is constant, its acceleration is zero. Which means no force is acting on the electron.
Since, $F = 0 \Rightarrow WD = 0$

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