Br2-OH-Hot- P -Q - P-Q -H- - Br2- P gives yellow precipitate with AgNO3- P and Q are-

The correct option is A Br^ , BrO^ Br^2 + OH (P) + (Q) (P) + (Q) + H → Br_2 ∴ (A) is correct. Br^ = P and BrO^ = Q ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Ion Electron Method

Br2+OH-Hot→ P...

Question

$B r_{2} + O H^{-} (H o t) \to (P) + (Q); (P) + (Q) + H^{+} \to B r_{2};$
$(P)$ gives yellow precipitate with $A g N O_{3}$ , $(P)$ and $(Q)$ are:

B r^{-}, B r O^{-}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B r^{-}, B r O_{3}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B r O^{-}, B r O_{3}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B r O^{-}, B r O 4^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

B r_{2} + 2 O H^{-} \to B r O^{-} + B r^{-} + 2 H_{2} O

B r_{2}

B r O^{-}

B r^{-}

B r^{-}

B r O_{x}^{-}

B r_{2}

(B r O_{3})^{-} a n d B r^{-}

\frac{d [B r O_{3}^{-}]}{d t} = k [B r O_{3}^{-}] [B r^{-}] {[H^{+}]}^{2}

B r_{2}

B r {O_{3}}^{-}

B r_{2}

N a O H

B r^{-}

B r {O_{3}}^{-}

B r_{2} + O H^{-} \to B r^{-} + B r O_{3}^{-} + H_{2} O

B r_{2}

Join BYJU'S Learning Program