Question

The perimeter of an isosceles triangle is $28cm.$ The unequal side is $10cm.$ Find the length of each equal side.

Answer 1

Let two equal sides of the isosceles triangle are ${}^{\prime }{a}^{\prime }$ and ${}^{\prime }{a}^{\prime }.$

The length of the unequal side $=10cm$

The perimeter of the given triangle $=28cm$

$10cm+a+a=28cm$ [$\because$ Perimeter $=$ Sum of all sides of a triangle. ]

$\Rightarrow 2a=18cm$

$\Rightarrow a=9cm$

Each equal side of the given isosceles triangle is $9cm.$