-Q- An aqueous solution of a non volatile non electrolyte freezes at mdash- 0-186 -176-C- Determine nbsp-the elevation of boiling point of the same solution- -Given- Kf of water- 1-86 K- Kg- nbsp-mol-1- nbsp-Kb of water 0-512 k-Kg-mol-1- nbsp-

Dear student #916;Tf nbsp; = Kf . m nbsp; nbsp;and nbsp; nbsp; #916;Tb = Kb . m where nbsp; Kf nbsp;and Kb are the molal freezing poin ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Boiling

Q. An aqueous...

Question

Q. An aqueous solution of a non volatile non electrolyte freezes at — 0.186 $°$ C. Determine
the elevation of boiling point of the same solution. [Given, $K_{f}$ of water= 1.86 K. Kg. $m o l^{- 1}$
$K_{b}$ of water 0.512 k.Kg. $m o l^{- 1}$ ]

Open in App

Solution

Suggest Corrections

Similar questions

K_{f} = 1.86

^{- 1}

K_{b} = 0.512

^{- 1}

298 K = 23.756

An aqueous solution freezes at -0.2°C. What is the molality of the solution. Determine also the-

(I) elevation in boiling point

(II) Lowering of vapour pressure

Given Kf=1.86°C Kg/mol Kb=0.512°C Kg/mol.

Vapour pressure of water=23.756 mm

- {0.186}^{o}

K_{f}

1.86 K k g m o l^{- 1}

K_{b}

0.512 K k g m o l^{- 1}

{100.17}^{\circ} C .

^{\circ} C

[K_{b}

K_{f}

0.512

{1.86}^{\circ} C / m

]

100.15^{\circ} C

K_{b}

K_{f}

0.512^{\circ} C kg/mol

1.86^{\circ} C kg/mol

Join BYJU'S Learning Program