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Question

evaluate the following;
a)cos 1050 degree
b)cosec (-585 degree)
c)cot 495 degree
d)tan 120 degree

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Solution

a cos 1050°= cos 1080-30=cos30=32b cosec-585=-cosec 585=-cosec360+225=-cosec225=-cosec180+45=cosec 45=2c cot 495=cot 360+135=cot 135=cot90+45=-tan 45=-1 ANS...d tan 120= tan 90+30=-cot 30 =-3 ANS...

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