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Question

HOW MANY GRAMS OF DIBASIC ACID (MOL WT.200)SHOULD BE PRESENT IN 100ml OF THE AQUEOUS SOLUTION TO GIVE 0.1N

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Solution

Dear Student,Normality =Gram equivalent of the soluteVolume of the solution in litreVolume of the solution in litre = 0.1 LGram equivalent of the solute =Mass of the solute in gramEquivalent mass of the soluteSolute = Dibasic acidEquivalent mass of acid =Molecular mass of acidBasicity=2002Basicity for dibasic acid = 2Normality =Mass of the solute in gramEquivalent mass of the solute×Volume of the solution in litreNormality = 0.10.1 =Mass of the solute acid in gram200/2 ×0.1Mass of the solute acid in gram =100 ×0.1×0.1 =1g AnswerRegards

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