If potential energy of a body of mass m on the surface of earth is taken as zero then its potential energy at height h above the surface of earth is (R is radius of earth and M is the mass of earth)
a)-GMm/(R+h)
b)-GMm/(h)
c)GMmh/R(R+h)
d)GMmh/(h+2R)

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Solution

The gravitational potential energy at height h,
$U = - \frac{G M m}{R + h} + \frac{G M m}{R} = \frac{G M m h}{R (R + h)}$

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If potential energy of a body of mass m on the surface of earth is taken as zero then its potential energy at height h above the surface of earth is (R is radius of earth and M is the mass of earth)a)-GMm/(R+h)b)-GMm/(h)c)GMmh/R(R+h)d)GMmh/(h+2R)

The gravitational potential energy at height h, U=-GMmR+h+GMmR=GMmhRR+h

If potential energy of a body of mass m on the surface of earth is taken as zero then its potential energy at height h above the surface of earth is (R is radius of earth and M is the mass of earth)
a)-GMm/(R+h)
b)-GMm/(h)
c)GMmh/R(R+h)
d)GMmh/(h+2R)

The gravitational potential energy at height h,
$U = - \frac{G M m}{R + h} + \frac{G M m}{R} = \frac{G M m h}{R (R + h)}$