Question

Solution A contains 10 g of glucose dissolved in 250 mL of water and solution B contains 30 g of sugar dissolved in 500 mL of water. Compare their molarities

Answer 1

Dear Student,

$$\begin{gathered} \mathrm{Molarity}=\frac{\mathrm{Mass}}{\mathrm{Molar}\mathrm{mass}}\times \frac{1000}{\mathrm{Volume}\mathrm{of}\mathrm{solution}\left(\mathrm{ml}\right)} \\ \mathrm{For}\mathrm{solution}\mathrm{A} \\ \mathrm{Molarity}=\frac{10}{180}\times \frac{1000}{250}=0.22\mathrm{M} \\ \mathrm{For}\mathrm{solution}\mathrm{B} \\ \mathrm{Molarity}=\frac{30}{342}\times \frac{1000}{500}=0.35\mathrm{M} \end{gathered}$$