The base of a triangular park is 420 metres and its height is 325 metres.Find the cost of levelling the park at the rate of Rs. 5 per 1000 metres square

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Solution

Area of the park= $\frac{1}{2}$ (base) (height)
= $\frac{1}{2} (420) (325) = (210) (325) = 68250 m^{2}$

It is given that cost of levelling the park is Rs 5 per 1000 metres square.

Therefore, total cost of levelling $= Rs \frac{5 \times 68250}{1000} = Rs \frac{5 \times 68250}{1000} = Rs 341.25$

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The base of a triangular park is 420 metres and its height is 325 metres.Find the cost of levelling the park at the rate of Rs. 5 per 1000 metres square

Area of the park=12(base) (height) =12420325=210325=68250m2 It is given that cost of levelling the park is Rs 5 per 1000 metres square. Therefore, total cost of levelling=Rs5×682501000=Rs5×682501000=Rs341.25

Area of the park= $\frac{1}{2}$ (base) (height)
= $\frac{1}{2} (420) (325) = (210) (325) = 68250 m^{2}$

It is given that cost of levelling the park is Rs 5 per 1000 metres square.

Therefore, total cost of levelling $= Rs \frac{5 \times 68250}{1000} = Rs \frac{5 \times 68250}{1000} = Rs 341.25$