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Question

Brakes are applied to a truck to produce an acceleration of 10 ms2​. If the truck takes 5 s to stop after applying the brakes, then find the distance covered by the truck before coming to rest.


A
250 m
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B
125 m
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C
125 m
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D
250 m
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Solution

The correct option is B 125 m

Given, final velocity, v=0, acceleration, a=10 ms2, time taken, t=5 s.
Let the initial velocity be u.
From the first equation of motion, v=u+at,
0=u+(10×5)
u=50 ms1
From third equation of motion, v2 = u2+2as,
0=502+2×10×s
s=125 m
Therefore, the truck will stop after 125 m.


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