BrCH 2 CHBrCH 2 Br alc-KOH - X - CH 3 O - Y - X - and - Y - respectively areA- H 2 C - CBrCH 2 Br - H 2 C - C Br CH 2 OCH 3B- BrHC - CHCH 2 Br - CH 3 OCH - CHCH 2 BrC- BrHC - CHCH 2 Br - BrCH - CHCH 2 OCH 3D- H 2 C - CBrCH 2 Br - H 2 C - C OCH 3 CH 2 Br

The correct option is C BrHC=CHCH_2Br, BrCH=CHCH_2OCH_3 BrCH_2CHBrCH_2Br CH_2=(less stable)Vinyl derivativeCBrCH_2Br or (more stable)AllylderivativeBrCH CHCH_2 ...

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Byju's Answer

Standard XII

Chemistry

Nucleophilic Substitution in Alkyl Halides

BrCH 2 CHBrCH...

Question

$B r C H_{2} C H B r C H_{2} B r a l c . K O H - ---- \to [X] C H_{3} O^{-} - --- \to Y; [X]$ and [Y] respectively are

$H_{2} C = C B r C H_{2} B r, H_{2} C = C (B r) C H_{2} O C H_{3}$

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$H_{2} C = C B r C H_{2} B r, H_{2} C = C (O C H_{3}) C H_{2} B r$

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$B r H C = C H C H_{2} B r, C H_{3} O C H = C H C H_{2} B r$

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$B r H C = C H C H_{2} B r, B r C H = C H C H_{2} O C H_{3}$

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Solution

The correct option is D
$B r H C = C H C H_{2} B r, B r C H = C H C H_{2} O C H_{3}$

$B r C H_{2} C H B r C H_{2} B r a l c . K O H - ---- \to (- H B r) C H_{2} = C B r C H_{2} B r V i n y l d e r i v a t i v e (l e s s s t a b l e) o r B r C H - C H C H_{2} B r A l l y l d e r i v a t i v e (m o r e s t a b l e)$
$B r C H_{2} C H B r C H_{2} B r [X]^{-} O C H_{3} - ------ \to n u c l e o p h i l i c s u b s t i t u t i o n B r C H - C H C H_{2} O C H_{3} [Y]$
The Br at allylic position is reactive, while Br at vinylic position is inert.

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BrCH2CHBrCH2Bralc.KOH−−−−−→[X]CH3O−−−−−→Y;[X] and [Y] respectively are

$B r C H_{2} C H B r C H_{2} B r a l c . K O H - ---- \to [X] C H_{3} O^{-} - --- \to Y; [X]$ and [Y] respectively are