You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Thermal Expansion

Breaking stre...

Question

Breaking stress of an iron rope is $6 \times 10^{6}$ pa. It is used to measure depth of sea. The maximum depth that can be measured with the iron rope is ( Youngs modulus of iron is $5 \times 10^{10} P a$ , density of iron is 4000 $k g / m^{3}$ , ( $g = 10 m / s^{2}$ )

150 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

175 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

200 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

250 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $150 m$
Breaking stress $= L ρ g$

$6 \times 10^{6} = L \times 4000 \times 10$

$L = 1.5 \times 100$

$L = 150 m$

The maximum depth that can be measured with the iron rope is 150 m

Suggest Corrections

Similar questions

Q. A metal rope of density

6000 k g / m^{3}

has breaking stress

9.8 \times 10^{8} N m^{- 2}

. This rope is used to measure the depth of the sea. Then the depth of the sea that can be measured with out breaking is _____

Q. A piece of iron of density

7800 k g / m^{3}

and volume

100 c m^{3}

is completely immersed in water. Calculate the upthrust on the iron piece.

[Take,

g = 10 m / s^{2}

A thick rope of rubber of density $1.5 \times 10^{3} kg/ m^{3}$ and Young's modulus $5 \times 10^{6} N/ m^{2}$ , $8 m$ length is hung from the ceiling of a room , the increases in its length due to its own weight is :

$(g = 10 m/ s^{2})$

Q. A piece of iron of density

7800 k g / m^{3}

and volume

100 c m^{3}

is completely immersed in water. Calculate the weight of the iron piece in air.

[Take,

g = 10 m / s^{2}

]

Q. Ratio of the weights of a

1 kg

block of iron and

1 kg

block of wood as measured by a spring balance is:
Given: Density of iron

= 7800 {kg/m}^{3}

, density of wood

= 800 {kg/m}^{3}

and density of air

= 1.293 {kg/m}^{3}

Join BYJU'S Learning Program

Breaking stress of an iron rope is 6×106 pa. It is used to measure depth of sea. The maximum depth that can be measured with the iron rope is ( Youngs modulus of iron is 5×1010 Pa, density of iron is 4000 kg/m3, (g=10m/s2)

The correct option is A 150 mBreaking stress =Lρg 6×106=L×4000×10 L=1.5×100 L=150m The maximum depth that can be measured with the iron rope is 150 m

Breaking stress of an iron rope is $6 \times 10^{6}$ pa. It is used to measure depth of sea. The maximum depth that can be measured with the iron rope is ( Youngs modulus of iron is $5 \times 10^{10} P a$ , density of iron is 4000 $k g / m^{3}$ , ( $g = 10 m / s^{2}$ )

The correct option is A $150 m$
Breaking stress $= L ρ g$

$6 \times 10^{6} = L \times 4000 \times 10$

$L = 1.5 \times 100$

$L = 150 m$

The maximum depth that can be measured with the iron rope is 150 m