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Question

# Briefly describe, how will you determine the specific latent heat of fusion of ice and what observation will you need?

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Solution

## The explanation for the observationWeight a clean and dry calorimeter with a stirrer.Fill the two-thirds of the calorimeter with water and weighed them.Note the initial temperature.Add some ice into the calorimeter.The calorimeter is placed inside a box.Stir until the ice completely melts.Note the final temperature.Weight the calorimeter and ice.Calculation of the latent heat of fusionThe specific latent heat of fusion of ice is given by:$\mathrm{L}=\frac{{\mathrm{m}}_{1}{\mathrm{s}}_{1}\left({\mathrm{t}}_{1}-{\mathrm{t}}_{2}\right)+\left({\mathrm{m}}_{2}-{\mathrm{m}}_{1}\right){\mathrm{s}}_{2}\left({\mathrm{t}}_{2}-{\mathrm{t}}_{1}\right)-\left({\mathrm{m}}_{3}-{\mathrm{m}}_{2}\right){\mathrm{s}}_{2}\left({\mathrm{t}}_{2}-\mathrm{t}\right)}{\left({\mathrm{m}}_{3}-{\mathrm{m}}_{2}\right)}$where,Mass of the calorimeter and stirrer = ${\mathrm{m}}_{1}$Mass of the calorimeter and water = ${\mathrm{m}}_{2}$Mass of the calorimeter, water and ice = ${\mathrm{m}}_{3}$Initial temperature = ${{\mathrm{t}}_{1}}^{\circ }\mathrm{C}$Final temperature = ${{\mathrm{t}}_{2}}^{\circ }\mathrm{C}$Temperature of ice = ${\mathrm{t}}^{\circ }\mathrm{C}$Specific latent heat of fusion of ice = $\mathrm{L}$Specific heat of the calorimeter = ${\mathrm{s}}_{1}$Specific heat of the water = ${\mathrm{s}}_{2}$

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