CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Briefly describe, how will you determine the specific latent heat of fusion of ice and what observation will you need?


Open in App
Solution

The explanation for the observation

  1. Weight a clean and dry calorimeter with a stirrer.
  2. Fill the two-thirds of the calorimeter with water and weighed them.
  3. Note the initial temperature.
  4. Add some ice into the calorimeter.
  5. The calorimeter is placed inside a box.
  6. Stir until the ice completely melts.
  7. Note the final temperature.
  8. Weight the calorimeter and ice.

Calculation of the latent heat of fusion

The specific latent heat of fusion of ice is given by:

L=m1s1t1-t2+m2-m1s2t2-t1-m3-m2s2t2-tm3-m2

where,

Mass of the calorimeter and stirrer = m1

Mass of the calorimeter and water = m2

Mass of the calorimeter, water and ice = m3

Initial temperature = t1C

Final temperature = t2C

Temperature of ice = tC

Specific latent heat of fusion of ice = L

Specific heat of the calorimeter = s1

Specific heat of the water = s2


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Change of State
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon