Btw 2 stations a train accelerates uniformly at first then moves with constant speed and finally retards uniformly. If the ratios of time taken are 1:8:1 and the greatest spewd is 60km/h, find the average speed over the whole journey
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Solution
The following velocity-time graph results
now, the total distance travelled will be given by the area under the vt curve. Now, as the geometry is trapezoidal in shape area = (1/2)[a + b] x h s = (1/2)[8t + 10t] x 60 or s = 540t now, the average speed will be vav = total distance travelled / total time taken = 540t / 10t thus, Vav = 54 km/hr