1
Question
Budhan covers a distance of 19 km in 2 hours by cycling one fourth of the time and walking the rest. The next day he cycles (at the same speed as before) for half the time and walks the rest (at the same speed as before) and covers 26 km in 2 hours. The speed in km/h at which Budhan walks is
Budhan covers a distance of 19 km in 2 hours by cycling one fourth of the time and walking the rest. The next day he cycles (at the same speed as before) for half the time and walks the rest (at the same speed as before) and covers 26 km in 2 hours. The speed in km/h at which Budhan walks is
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Solution
The correct option is D
6
Let cycling speed=C
and walking speed=W
C(12)+W(32)=19 ....(i)
C+W=26 ....(ii)
On Solving eq. (i) and (ii) we get,
W=6km/hr
6
Let cycling speed=C
and walking speed=W
C(12)+W(32)=19 ....(i)
C+W=26 ....(ii)
On Solving eq. (i) and (ii) we get,
W=6km/hr
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