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Standard XII

Physics

Second Law of Motion

Bullets of 0....

Question

Bullets of 0.03 kg mass each hit a plate at the rate of 200 bullets per second with a velocity of 30 m/s. Their average force acting on the plate in newton is

120

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180

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300

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480

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Solution

The correct option is A 180
Average force on the plate is change in momentum per unit time.

$F = \frac{n m v}{t} = \frac{200 \times 0.03 \times 30}{1} = 180 N$ .

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Bullets of 0.03 kg mass each hit a plate at the rate of 200 bullets per second with a velocity of 30 m/s. Their average force acting on the plate in newton is

The correct option is A 180Average force on the plate is change in momentum per unit time.F=nmvt=200×0.03×301=180N.

The correct option is A 180
Average force on the plate is change in momentum per unit time.

$F = \frac{n m v}{t} = \frac{200 \times 0.03 \times 30}{1} = 180 N$ .