Butan-2-ol and pentan-2-ol are:

optically active compound/s

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optically inactive compound/s

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both have chiral carbon at 2nd position

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both

A

and

C

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Solution

The correct option is D both $A$ and $C$

Butan-2-ol $C H_{3} - C H_{2} - C H (O H) - C H_{3}$ and pentan-2-ol $C H_{3} - C H_{2} - C H_{2} - C H (O H) - C H_{3}$ are optically active compounds.

Both have chiral carbon at 2nd position. A chiral C atom is C atom attached to four different atoms or groups.

Hence, option $D$ is correct.

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Similar questions

Arrange the following compounds in increasing order of boiling point. Propan - 1 - ol, butan - 1 - ol, butan - 2 - ol, pentan - 1 - ol
(a) Propan-1-ol, butan-2-ol, butan - 1 - ol, pentan-1-o|
(b) Propan-1-ol, butan - 1 - ol, butan-2-ol, pentan-1-ol
(c) Propan-1-ol, butan-2-ol, butan-1-ol, pentan-1-ol
(d) Propan-1-ol, butan-1-ol, butan-2-ol, pentan-1-ol

Q. Arrange the following compounds in increasing order of boiling point.

Propan - 1 - ol, butan - 1 -ol, butan - 2- ol , pentan -1 -ol

Q. Arrange the following compounds in increasing order of boiling points . Propan-1-ol , butan-1-ol , butan-2-ol, pentan-1-ol.

Q. Statement 1: Pentan-2-ol exhibits optical isomerism.

Statement 2: Pentan-2-ol has one chiral carbon.

Q. What type of isomerism exists between the following pairs of compounds?
(i) Pentan-1-ol and 3-Methylbutan-1-ol
(ii) Ethanol and Dimethyl ether
(iii) Butan-1-ol and Butan-2-ol

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Butan-2-ol and pentan-2-ol are:

The correct option is D both A and CButan-2-ol CH3−CH2−CH(OH)−CH3 and pentan-2-ol CH3−CH2−CH2−CH(OH)−CH3 are optically active compounds. Both have chiral carbon at 2nd position. A chiral C atom is C atom attached to four different atoms or groups. Hence, option D is correct.