By applying the brakes without causing a skid, the driver of a car is able to stop his cart with in a distance of $5 m$ , if it is going at $36 k m p h$ . If the car were going at $72 k m p h$ , using the same brakes, he can stop the car over a distance of

10 m

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2.5 m

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20 m

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40 m

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Solution

The correct option is C $20 m$
In kinematic equation, final velocity $v = 0$ .
acceleration is constant (so we assume) and is negative
$s \propto u^{2}$
In 1st scenario $s = 5 m, u = 36 k m p h = 10 m / s$
In 2nd scenario $s = ?$
$u = 72 k m p h = 20 m / s$
$s = 2^{2} \times 5 m = 20 m$

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