Question

By constructing a rectangle $WXYZ$, of height $=$ $5cm$ and base $=4.8$ $cm$, find the length of the diagonal of the rectangle (in $cm$) up to the nearest integer.

Answer 1

Fist we draw a line YZ=4.8 cm

Make angle 90 at point Y ,And draw a line cut at point Y, YX =5 cm by compass

After that with compass make cut from point X ,4.8 cm and cut at point Z , 5 cm both cuts meeting at point W

Join W from X and Z we get rectangle XYZW

As per Pythagoras theorem

$(xz{)}^2=(xy{)}^2+(YZ{)}^2=(5{)}^2+(4.8{)}^2=25+23.04=48.04$

Then diagonal of rectangle =XZ=$=6.93\approx 7$